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(y^2/25)=3
We move all terms to the left:
(y^2/25)-(3)=0
We get rid of parentheses
y^2/25-3=0
We multiply all the terms by the denominator
y^2-3*25=0
We add all the numbers together, and all the variables
y^2-75=0
a = 1; b = 0; c = -75;
Δ = b2-4ac
Δ = 02-4·1·(-75)
Δ = 300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{300}=\sqrt{100*3}=\sqrt{100}*\sqrt{3}=10\sqrt{3}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{3}}{2*1}=\frac{0-10\sqrt{3}}{2} =-\frac{10\sqrt{3}}{2} =-5\sqrt{3} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{3}}{2*1}=\frac{0+10\sqrt{3}}{2} =\frac{10\sqrt{3}}{2} =5\sqrt{3} $
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